solve for c.\n$\frac{2}{3}c - 2 = 2 + c$\n$c = square$
solve for c.\n$\frac{2}{3}c - 2 = 2 + c$\n$c = square$
Answer
Explanation:
Step1: Move terms with c to one - side
Subtract c from both sides: $\frac{2}{3}c - c-2=2 + c - c$. Simplify the left - hand side: $\frac{2}{3}c - c=\frac{2}{3}c-\frac{3}{3}c=-\frac{1}{3}c$. So, $-\frac{1}{3}c - 2=2$.
Step2: Isolate the term with c
Add 2 to both sides: $-\frac{1}{3}c-2 + 2=2 + 2$. We get $-\frac{1}{3}c=4$.
Step3: Solve for c
Multiply both sides by - 3: $c=4\times(-3)$.
Answer:
$c=-12$