solve and graph the following inequality: -4 + 3x < -9x + 5

Explanation:

Step1: Add 9x to both sides

$ - 4+3x + 9x<-9x + 9x+5$ $ - 4 + 12x<5$

Step2: Add 4 to both sides

$ - 4+4 + 12x<5 + 4$ $12x<9$

Step3: Divide both sides by 12

$x<\frac{9}{12}=\frac{3}{4}$

Answer:

$x<\frac{3}{4}$ To graph, on the number - line, draw an open circle at $\frac{3}{4}$ (because the inequality is strict, $x$ cannot equal $\frac{3}{4}$) and shade the line to the left of $\frac{3}{4}$.