solve the inequality below: -12 - 3x ≥ 1/3(17 - 9x)

Explanation:

Step1: Expand the right - hand side

$$-12 - 3x\geq\frac{17}{3}- 3x$$

Step2: Add (3x) to both sides

$$-12\geq\frac{17}{3}$$ Since (- 12=-\frac{36}{3}) and (-\frac{36}{3}<\frac{17}{3}), this inequality is always false.

Answer:

There is no solution for (x) (the solution set is (\varnothing)).