solve the inequality. 2x - 9 ≤ 1 x ≤ ?
solve the inequality. 2x - 9 ≤ 1 x ≤ ?
Answer
Explanation:
Step1: Add 9 to both sides
$$2x - 9+9\leq1 + 9$$ $$2x\leq10$$
Step2: Divide both sides by 2
$$\frac{2x}{2}\leq\frac{10}{2}$$ $$x\leq5$$
Answer:
$5$
solve the inequality. 2x - 9 ≤ 1 x ≤ ?
$$2x - 9+9\leq1 + 9$$ $$2x\leq10$$
$$\frac{2x}{2}\leq\frac{10}{2}$$ $$x\leq5$$
$5$