solve the inequality.\n2(4 + 2x)≥5x + 5\no x≤ - 2\no x≥ - 2\no x≤3\no x≥3

Explanation:

Step1: Expand the left - hand side

$2(4 + 2x)=8 + 4x$, so the inequality becomes $8+4x\geq5x + 5$.

Step2: Move the terms with $x$ to one side

Subtract $4x$ from both sides: $8\geq5x-4x + 5$, which simplifies to $8\geq x + 5$.

Step3: Solve for $x$

Subtract 5 from both sides: $8 - 5\geq x$, so $x\leq3$.

Answer:

$x\leq3$