solve the inequality. 2(4x - 3) ≥ -3(3x) + 5x?\no x ≥ 0.5\no x ≥ 2\no (-∞, 0.5\no (-∞, 2

Answer:

A. $x\geq0.5$

Explanation:

Step1: Expand both sides

$2(4x - 3)=8x-6$ and $-3(3x)+5x=-9x + 5x=-4x$. So the inequality becomes $8x-6\geq - 4x$.

Step2: Add $4x$ to both sides

$8x+4x-6\geq - 4x+4x$, which simplifies to $12x-6\geq0$.

Step3: Add 6 to both sides

$12x-6 + 6\geq0 + 6$, resulting in $12x\geq6$.

Step4: Divide both sides by 12

$\frac{12x}{12}\geq\frac{6}{12}$, so $x\geq0.5$.