solve for $x$ to the nearest tenth.

solve for $x$ to the nearest tenth.

solve for $x$ to the nearest tenth.

Answer

Explanation:

Step1: Create right triangle base

Subtract the vertical sides: $5 - 3 = 2$

Step2: Apply Pythagorean theorem

Use legs 4 and 2 to find $x$: $$x = \sqrt{4^2 + 2^2}$$

Step3: Calculate and round to nearest tenth

Simplify and compute: $x = \sqrt{16 + 4} = \sqrt{20} \approx 4.5$

Answer:

4.5