solve the quadratic equation.\n$x^{2}+9x - 36 = 0$\n(1 point)\n$x = 3$ or 12\n$x = 3$ or $-12$\n$x = 6$ or…

solve the quadratic equation.\n$x^{2}+9x - 36 = 0$\n(1 point)\n$x = 3$ or 12\n$x = 3$ or $-12$\n$x = 6$ or $-6$\nno real solution

solve the quadratic equation.\n$x^{2}+9x - 36 = 0$\n(1 point)\n$x = 3$ or 12\n$x = 3$ or $-12$\n$x = 6$ or $-6$\nno real solution

Answer

Explanation:

Step1: Factor the quadratic equation

For the quadratic equation (x^{2}+9x - 36=0), we need to find two numbers (a) and (b) such that (a\times b=-36) and (a + b=9). The numbers are (12) and (- 3) since (12\times(-3)=-36) and (12+( - 3)=9). So, (x^{2}+9x - 36=(x + 12)(x - 3)=0)

Step2: Use the zero - product property

If ((x + 12)(x - 3)=0), then either (x+12 = 0) or (x - 3=0) For (x+12 = 0), we get (x=-12) For (x - 3=0), we get (x = 3)

Answer:

(x = 3) or (x=-12) (corresponding to the second option (x = 3) or (-12))