solve for (x). round to the nearest tenth of a degree, if necessary.

solve for (x). round to the nearest tenth of a degree, if necessary.
Answer
Explanation:
Step1: Identify the trigonometric ratio
In right - triangle (PQR) with right - angle at (Q), we know the opposite side ((QR = 3.3)) and the hypotenuse ((PR=6)) with respect to angle (x). We use the sine ratio (\sin x=\frac{\text{opposite}}{\text{hypotenuse}}). (\sin x=\frac{3.3}{6})
Step2: Calculate the value of (\sin x)
(\sin x = 0.55)
Step3: Find the value of (x)
We know that if (\sin x=a), then (x = \sin^{- 1}(a)). So (x=\sin^{-1}(0.55)). Using a calculator, (x=\sin^{-1}(0.55)\approx33.4^{\circ})
Answer:
(33.4^{\circ})