solve for x. round to the nearest tenth of a degree, if necessary.\nanswer attempt 1 out of 2\nx =

solve for x. round to the nearest tenth of a degree, if necessary.\nanswer attempt 1 out of 2\nx =

solve for x. round to the nearest tenth of a degree, if necessary.\nanswer attempt 1 out of 2\nx =

Answer

Explanation:

Step1: Identify trigonometric ratio

In right - triangle OPQ, we know the opposite side (OP = 29) and the hypotenuse (OQ = 59) with respect to angle (x). We use the sine ratio (\sin x=\frac{\text{opposite}}{\text{hypotenuse}}). So, (\sin x=\frac{29}{59}).

Step2: Solve for (x)

We take the inverse - sine of both sides: (x = \sin^{- 1}(\frac{29}{59})). Using a calculator, (x=\sin^{-1}(\frac{29}{59})\approx30.0^{\circ}).

Answer:

(30.0)