solve for ( x ). round to the nearest tenth, if necessary.

Explanation:

Step1: Identify trigonometric ratio

We use sine: $\sin(Q) = \frac{SR}{SQ}$

Step2: Substitute known values

$\sin(40^\circ) = \frac{35}{x}$

Step3: Rearrange to solve for $x$

$x = \frac{35}{\sin(40^\circ)}$

Step4: Calculate and round

$\sin(40^\circ) \approx 0.6428$, so $x \approx \frac{35}{0.6428} \approx 54.5$

Answer:

$54.5$