solve for (x). round to the nearest tenth, if necessary.\nanswer attempt 1 out of 2\n(x=)

solve for (x). round to the nearest tenth, if necessary.\nanswer attempt 1 out of 2\n(x=)
Answer
Answer:
$x\approx44.6$
Explanation:
Step1: Use tangent function
In right - triangle $JKL$, $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$. Here, $\theta = 28^{\circ}$ and the adjacent side to $\angle L$ is $x$ and the opposite side is $95$. So, $\tan(28^{\circ})=\frac{95}{x}$.
Step2: Solve for $x$
We can rewrite the equation as $x=\frac{95}{\tan(28^{\circ})}$. Since $\tan(28^{\circ})\approx0.5317$, then $x=\frac{95}{0.5317}\approx44.6$.