solve for x. round to the nearest tenth. (only write the number)

solve for x. round to the nearest tenth. (only write the number)
Answer
Explanation:
Step1: Identify trigonometric ratio
We use sine for the $12^\circ$ angle: $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$, so $\sin(12^\circ) = \frac{x}{29}$
Step2: Isolate x to solve
Rearrange to solve for $x$: $x = 29 \times \sin(12^\circ)$ Calculate $\sin(12^\circ) \approx 0.2079$, then $x \approx 29 \times 0.2079$
Step3: Compute and round
$29 \times 0.2079 \approx 6.0291$, round to nearest tenth: $6.0$
Answer:
6.0