solve $sqrt{x + 8}-1 = 3$

Explanation:

Step1: Isolate the square - root term

Add 1 to both sides of the equation $\sqrt{x + 8}-1 = 3$. $\sqrt{x + 8}=3 + 1$ $\sqrt{x + 8}=4$

Step2: Eliminate the square - root

Square both sides of the equation $\sqrt{x + 8}=4$. $(\sqrt{x + 8})^2=4^2$ $x + 8=16$

Step3: Solve for x

Subtract 8 from both sides of the equation $x + 8=16$. $x=16 - 8$ $x = 8$

Answer:

$x = 8$