solve the system of equations.\n- 12x - 5y = 40\n12x - 11y = 88\nx = \n y =

Explanation:

Step1: Add the two equations

Adding the equations (-12x - 5y=40) and (12x - 11y = 88) eliminates (x). ((-12x-5y)+(12x - 11y)=40 + 88) (-12x-5y+12x - 11y=128) (-16y=128)

Step2: Solve for (y)

Divide both sides of (-16y = 128) by (-16). (y=\frac{128}{-16}=-8)

Step3: Substitute (y = - 8) into the first - equation

Substitute (y=-8) into (-12x-5y = 40). (-12x-5\times(-8)=40) (-12x + 40=40) (-12x=40 - 40) (-12x=0) (x = 0)

Answer:

(x = 0) (y=-8)