solve the system of equations.\ny = 3x - 4\ny = -3x + 8\nx = \ny =

Explanation:

Step1: Set the two equations equal

Since both equal $y$, we have $3x - 4=-3x + 8$.

Step2: Solve for $x$

Add $3x$ to both sides: $3x+3x - 4=-3x+3x + 8$, which simplifies to $6x-4 = 8$. Then add 4 to both sides: $6x-4 + 4=8 + 4$, so $6x=12$. Divide both sides by 6: $x=\frac{12}{6}=2$.

Step3: Solve for $y$

Substitute $x = 2$ into the first - equation $y = 3x-4$. Then $y=3\times2-4=6 - 4=2$.

Answer:

$x = 2$ $y = 2$