solve the system of equations.\n-5y - 10x = 45\n-3y + 10x = -5\nx = \n\ny = \n

Explanation:

Step1: Add the two equations

Adding $-5y - 10x=45$ and $-3y + 10x=-5$ will eliminate $x$. $(-5y - 10x)+(-3y + 10x)=45+( - 5)$ $-5y-3y-10x + 10x=40$ $-8y=40$

Step2: Solve for $y$

Divide both sides of $-8y = 40$ by $-8$. $y=\frac{40}{-8}=-5$

Step3: Substitute $y$ into an equation

Substitute $y = - 5$ into $-3y + 10x=-5$. $-3\times(-5)+10x=-5$ $15 + 10x=-5$

Step4: Solve for $x$

Subtract 15 from both sides: $10x=-5 - 15=-20$. Then divide both sides by 10: $x=\frac{-20}{10}=-2$

Answer:

$x=-2$ $y=-5$