solve the system of equations graphed on the coordinate axes below.\ny = -\\frac{4}{3}x - 1\ny =…

Explanation:

Step1: Set the two equations equal.

Since (y =-\frac{4}{3}x - 1) and (y=\frac{4}{3}x + 7), we set (-\frac{4}{3}x-1=\frac{4}{3}x + 7).

Step2: Solve for (x).

First, add (\frac{4}{3}x) to both sides: (-1=\frac{4}{3}x+\frac{4}{3}x + 7). Combining like - terms gives (-1=\frac{8}{3}x + 7). Then subtract 7 from both sides: (-1 - 7=\frac{8}{3}x), so (-8=\frac{8}{3}x). Multiply both sides by (\frac{3}{8}): (x=-8\times\frac{3}{8}=-3).

Step3: Solve for (y).

Substitute (x = - 3) into (y=\frac{4}{3}x + 7). (y=\frac{4}{3}\times(-3)+7). (y=-4 + 7=3).

Answer:

(x=-3,y = 3)