solve the system of linear equations by graphing. round the solution to the nearest tenth as needed.\ny +…

solve the system of linear equations by graphing. round the solution to the nearest tenth as needed.\ny + 2.3 = 0.45x\n-2y = 4.2x - 7.8\n(2.4, -1.2)\n(-1, 2.5)\nno solution\ninfinitely many solutions

solve the system of linear equations by graphing. round the solution to the nearest tenth as needed.\ny + 2.3 = 0.45x\n-2y = 4.2x - 7.8\n(2.4, -1.2)\n(-1, 2.5)\nno solution\ninfinitely many solutions

Answer

Answer:

A. (2.4, -1.2)

Explanation:

Step1: Rewrite equations in slope - intercept form

For $y + 2.3=0.45x$, we get $y = 0.45x-2.3$. For $-2y = 4.2x - 7.8$, divide both sides by $-2$: $y=-2.1x + 3.9$.

Step2: Analyze slopes and y - intercepts

The first equation has slope $m_1 = 0.45$ and y - intercept $b_1=-2.3$. The second has slope $m_2=-2.1$ and y - intercept $b_2 = 3.9$. Since $m_1\neq m_2$, the lines intersect at a single point.

Step3: Check the given point

Substitute $x = 2.4$ and $y=-1.2$ into the first equation: Left - hand side: $-1.2 + 2.3=1.1$. Right - hand side: $0.45\times2.4 = 1.08\approx1.1$. Substitute into the second equation: Left - hand side: $-2\times(-1.2)=2.4$. Right - hand side: $4.2\times2.4-7.8=10.08 - 7.8 = 2.28\approx2.4$. So the solution is $(2.4,-1.2)$.