solve the system by substitution.\n-6x - 2y = 20\n3y = x

Explanation:

Step1: Substitute $x$ in the first - equation

Given $x = 3y$, substitute it into $-6x-2y=20$. We get $-6(3y)-2y = 20$.

Step2: Simplify the left - hand side

Expand $-6(3y)-2y$: $-18y-2y=20$, which simplifies to $-20y = 20$.

Step3: Solve for $y$

Divide both sides of $-20y = 20$ by $-20$. So, $y=\frac{20}{-20}=-1$.

Step4: Solve for $x$

Substitute $y = - 1$ into $x = 3y$. Then $x=3\times(-1)=-3$.

Answer:

$x=-3,y = - 1$