solve the triangle.\nb = (square^{circ}) (do not round until the final answer. then round to the nearest…

solve the triangle.\nb = (square^{circ}) (do not round until the final answer. then round to the nearest degree as needed.)\nb (approx) (square) (do not round until the final answer. then round to the nearest tenth as needed.)\nc (approx) (square) (do not round until the final answer. then round to the nearest tenth as needed.)
Answer
Explanation:
Step1: Find angle B
The sum of angles in a triangle is 180°. So $B = 180^{\circ}-A - C$. Given $A = 35^{\circ}$ and $C=76^{\circ}$, then $B=180 - 35-76=69^{\circ}$.
Step2: Use the Law of Sines to find side b
The Law of Sines states that $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$. We know $a = 9$, $A = 35^{\circ}$, and $B=69^{\circ}$. So $b=\frac{a\sin B}{\sin A}=\frac{9\times\sin69^{\circ}}{\sin35^{\circ}}$. Since $\sin69^{\circ}\approx0.9346$ and $\sin35^{\circ}\approx0.5736$, then $b=\frac{9\times0.9346}{0.5736}\approx14.7$.
Step3: Use the Law of Sines to find side c
Using $\frac{a}{\sin A}=\frac{c}{\sin C}$, with $a = 9$, $A = 35^{\circ}$, and $C = 76^{\circ}$. So $c=\frac{a\sin C}{\sin A}=\frac{9\times\sin76^{\circ}}{\sin35^{\circ}}$. Since $\sin76^{\circ}\approx0.9703$ and $\sin35^{\circ}\approx0.5736$, then $c=\frac{9\times0.9703}{0.5736}\approx15.2$.
Answer:
$B = 69^{\circ}$ $b\approx14.7$ $c\approx15.2$