solve. 4|x - 1|+3 > 7\ntrue or false: the following is the graph of the solution to the inequality above.

Explanation:

Step1: Isolate the absolute - value expression

Subtract 3 from both sides of the inequality $4|x - 1|+3>7$. $4|x - 1|+3 - 3>7 - 3$ $4|x - 1|>4$ Then divide both sides by 4: $|x - 1|>1$.

Step2: Solve the absolute - value inequality

If $|x - 1|>1$, then we have two cases: Case 1: $x−1>1$. Add 1 to both sides: $x−1 + 1>1 + 1$, so $x>2$. Case 2: $x−1< - 1$. Add 1 to both sides: $x−1 + 1< - 1+1$, so $x<0$. The solution of the inequality $4|x - 1|+3>7$ is $x<0$ or $x>2$. The graph shows an open - circle at $x = 0$ with the line going to the left and an open - circle at $x = 2$ with the line going to the right, which represents $x<0$ or $x>2$.

Answer:

True