if (f(x)=sqrt{4x + 9}+2), which inequality can be used to find the domain of (f(x))?\n(sqrt{4x}geq0)\n(4x +…

Explanation:

Step1: Recall domain - rule for square - root

The expression inside a square - root $\sqrt{u}$ must satisfy $u\geq0$ for the function to be a real - valued function. In the function $f(x)=\sqrt{4x + 9}+2$, the part under the square - root is $4x + 9$.

Step2: Set up the inequality

We set $4x+9\geq0$ to ensure that the square - root $\sqrt{4x + 9}$ is a real number.

Answer:

B. $4x + 9\geq0$