if (f(x)=sqrt{x - 3}), which inequality can be used to find the domain of (f(x))?\n(sqrt{x - 3}geq0)\n(x…
if (f(x)=sqrt{x - 3}), which inequality can be used to find the domain of (f(x))?\n(sqrt{x - 3}geq0)\n(x - 3geq0)\n(sqrt{x - 3}leq0)\n(x - 3leq0)
Answer
Explanation:
Step1: Recall domain - rule for square - root
The expression inside a square - root $\sqrt{a}$ must satisfy $a\geq0$ for the function to be a real - valued function.
Step2: Identify the expression inside the square - root
For the function $f(x)=\sqrt{x - 3}$, the expression inside the square - root is $x-3$.
Answer:
B. $x - 3\geq0$