what is $sqrt3{343}$?

Answer:

7

Explanation:

Step1: Recall cube - root definition

The cube - root of a number $x$, denoted as $\sqrt[3]{x}$, is a number $y$ such that $y^3=x$.

Step2: Find the number whose cube is 343

We know that $7\times7\times7 = 7^3=343$. So, $\sqrt[3]{343}=7$.