what is $sqrt4{7^{3}}$ in exponential form?\n$7^{\frac{3}{4}}$\n$7^{\frac{4}{3}}$\n$7^{-\frac{4}{3}}$\ndone

Explanation:

Step1: Recall radical - exponent rule

The rule for converting a radical $\sqrt[n]{a^m}$ to exponential form is $a^{\frac{m}{n}}$, where $n$ is the index of the radical and $m$ is the exponent of the radicand.

Step2: Identify values of $m$ and $n$

In $\sqrt[4]{7^3}$, $n = 4$ (the index of the fourth - root) and $m=3$ (the exponent of 7).

Step3: Write in exponential form

Using the rule $\sqrt[n]{a^m}=a^{\frac{m}{n}}$, we get $7^{\frac{3}{4}}$.

Answer:

$7^{\frac{3}{4}}$