what is the square root of $m^{6}$?\n$m^{2}$\n$m^{3}$\n$m^{4}$\n$m^{5}$
what is the square root of $m^{6}$?\n$m^{2}$\n$m^{3}$\n$m^{4}$\n$m^{5}$
Answer
Explanation:
Step1: Recall square - root and exponent rule
The square root of a number is the same as raising it to the power of $\frac{1}{2}$. So, $\sqrt{m^{6}}=(m^{6})^{\frac{1}{2}}$.
Step2: Apply power - of - a - power rule
According to the power - of - a - power rule $(a^{m})^{n}=a^{mn}$. Here, $a = m$, $m = 6$, and $n=\frac{1}{2}$. Then $(m^{6})^{\frac{1}{2}}=m^{6\times\frac{1}{2}}$.
Step3: Calculate the exponent
$6\times\frac{1}{2}=3$, so $m^{6\times\frac{1}{2}}=m^{3}$.
Answer:
B. $m^{3}$