which statement about $6x^{2}+7x - 10$ is true?\none of the factors is $(x + 2)$.\none of the factors is…

which statement about $6x^{2}+7x - 10$ is true?\none of the factors is $(x + 2)$.\none of the factors is $(3x - 2)$.\none of the factors is $(2x + 5)$.\none of the factors is $(x - 5)$.

which statement about $6x^{2}+7x - 10$ is true?\none of the factors is $(x + 2)$.\none of the factors is $(3x - 2)$.\none of the factors is $(2x + 5)$.\none of the factors is $(x - 5)$.

Answer

Explanation:

Step1: Factor the quadratic expression

We use the AC - method for factoring (ax^{2}+bx + c) (here (a = 6), (b=7), (c=-10)). First, find (ac=6\times(- 10)=-60). We need to find two numbers that multiply to (-60) and add up to (7). The numbers are (12) and (-5) since (12\times(-5)=-60) and (12+( - 5)=7). Then rewrite the middle - term: (6x^{2}+12x-5x - 10). Group the terms: ((6x^{2}+12x)-(5x + 10)=6x(x + 2)-5(x + 2)=(6x - 5)(x + 2)).

Answer:

A. One of the factors is ((x + 2))