which statement describes how to solve $sqrt{3x + 4}=sqrt{3x}+4$?\nsquare both sides once and then solve the…

Explanation:

Step1: Square both sides first

[(\sqrt{3x + 4})^2=(\sqrt{3x}+4)^2] [3x + 4=3x + 8\sqrt{3x}+16] This is not a linear or quadratic - equation yet.

Step2: Isolate the square - root term

[8\sqrt{3x}=3x + 4-(3x + 16)] [8\sqrt{3x}=- 12]

Step3: Square both sides again

[(8\sqrt{3x})^2=(-12)^2] [64\times3x = 144] [192x=144] This is a linear equation. We squared both sides twice and then got a linear equation.

Answer:

Square both sides twice and then solve the resulting linear equation.