which statement is true about the function $f(x)=sqrt{-x}$?\nthe domain of the graph is all real…

Explanation:

Step1: Recall domain definition

For $\sqrt{-x}$ to be a real - valued function, the expression under the square - root must be non - negative. So, $-x\geq0$.

Step2: Solve for x

Multiply both sides of the inequality $-x\geq0$ by $- 1$. When we multiply an inequality by a negative number, the direction of the inequality sign changes. We get $x\leq0$. So the domain of $y = \sqrt{-x}$ is all real numbers less than or equal to $0$.

Step3: Analyze the range

The square - root function $\sqrt{-x}\geq0$ for all $x$ in the domain. That is, the output of the square - root function is always non - negative.

Answer:

The domain of the graph is all real numbers less than or equal to 0.