step 2: $\frac{\frac{y - 2x^{2}}{x^{2}y}}{\frac{y - 2x^{2}}{1}}$ step 3: $\frac{y - 2x^{2}}{x^{2}y}cdot\frac{…

step 2: $\frac{\frac{y - 2x^{2}}{x^{2}y}}{\frac{y - 2x^{2}}{1}}$ step 3: $\frac{y - 2x^{2}}{x^{2}y}cdot\frac{1}{y - 2x^{2}}$ what should mrs. cho do next? find a common denominator for the two fractions. divide the numerator and denominator of the first fraction by $x^{2}$ and $y$. multiply the numerators, multiply the denominators, and then simplify. multiply the first fraction by the reciprocal of the second fraction.

step 2: $\frac{\frac{y - 2x^{2}}{x^{2}y}}{\frac{y - 2x^{2}}{1}}$ step 3: $\frac{y - 2x^{2}}{x^{2}y}cdot\frac{1}{y - 2x^{2}}$ what should mrs. cho do next? find a common denominator for the two fractions. divide the numerator and denominator of the first fraction by $x^{2}$ and $y$. multiply the numerators, multiply the denominators, and then simplify. multiply the first fraction by the reciprocal of the second fraction.

Answer

Answer:

C. Multiply the numerators, multiply the denominators, and then simplify.

Explanation:

Step1: Analyze the current step

We have $\frac{y - 2x^{2}}{x^{2}y}\cdot\frac{1}{y - 2x^{2}}$, which is a multiplication of two fractions.

Step2: Recall fraction - multiplication rule

For two fractions $\frac{a}{b}$ and $\frac{c}{d}$, the product is $\frac{a\cdot c}{b\cdot d}$. So for $\frac{y - 2x^{2}}{x^{2}y}\cdot\frac{1}{y - 2x^{2}}$, we multiply numerators $(y - 2x^{2})\times1$ and denominators $x^{2}y\times(y - 2x^{2})$ and then simplify.