some of the steps in the derivation of the quadratic formula are shown.\nstep 4: $\frac{-4ac +…

some of the steps in the derivation of the quadratic formula are shown.\nstep 4: $\frac{-4ac + b^{2}}{4a}=a(x+\frac{b}{2a})^{2}$\nstep 5: $(\frac{1}{a})\frac{b^{2}-4ac}{4a}=(\frac{1}{a})a(x+\frac{b}{2a})^{2}$\nstep 6: $\frac{b^{2}-4ac}{4a^{2}}=(x+\frac{b}{2a})^{2}$\nstep 7: $\frac{pmsqrt{b^{2}-4ac}}{2a}=x+\frac{b}{2a}$\nwhich best explains why the expression $pmsqrt{b^{2}-4ac}$ cannot be rewritten as $bpmsqrt{-4ac}$ during the next step?\nnegative values, like -4ac, do not have a square root.\nthe $pm$ symbol prevents the square root from being evaluated.\nthe square root of terms separated by addition and subtraction cannot be calculated individually.\nthe entire term $b^{2}-4ac$ must be divided by 2a before its square root can be determined.

some of the steps in the derivation of the quadratic formula are shown.\nstep 4: $\frac{-4ac + b^{2}}{4a}=a(x+\frac{b}{2a})^{2}$\nstep 5: $(\frac{1}{a})\frac{b^{2}-4ac}{4a}=(\frac{1}{a})a(x+\frac{b}{2a})^{2}$\nstep 6: $\frac{b^{2}-4ac}{4a^{2}}=(x+\frac{b}{2a})^{2}$\nstep 7: $\frac{pmsqrt{b^{2}-4ac}}{2a}=x+\frac{b}{2a}$\nwhich best explains why the expression $pmsqrt{b^{2}-4ac}$ cannot be rewritten as $bpmsqrt{-4ac}$ during the next step?\nnegative values, like -4ac, do not have a square root.\nthe $pm$ symbol prevents the square root from being evaluated.\nthe square root of terms separated by addition and subtraction cannot be calculated individually.\nthe entire term $b^{2}-4ac$ must be divided by 2a before its square root can be determined.

Answer

Answer:

The square root of terms separated by addition and subtraction cannot be calculated individually.

Explanation:

Step1: Recall square - root property

The square root $\sqrt{a\pm b}\neq\sqrt{a}\pm\sqrt{b}$. In the expression $\pm\sqrt{b^{2}-4ac}$, $b^{2}$ and $4ac$ are separated by subtraction. So we cannot rewrite $\pm\sqrt{b^{2}-4ac}$ as $b\pm\sqrt{- 4ac}$.