a student says that if $5x^2 = 20$, then $x$ must be equal to 2. do you agree or disagree with the student…
a student says that if $5x^2 = 20$, then $x$ must be equal to 2. do you agree or disagree with the student? justify your answer.
Answer
Explanation:
Step1: Solve the equation (5x^2 = 20)
Divide both sides by 5: (x^2=\frac{20}{5}=4)
Step2: Find the square roots of 4
The square root of a number (a) is a value (b) such that (b^2 = a). For (x^2 = 4), (x=\pm\sqrt{4}=\pm2) So (x) can be 2 or -2, not just 2.
Answer:
I disagree with the student. Solving (5x^2 = 20) gives (x^2 = 4), so (x=\pm2) (both 2 and -2 satisfy the equation), not just (x = 2).