what substitution should be used to rewrite 6(x + 5)^2+5(x + 5)-4 = 0 as a quadratic equation?\no u=(x +…

what substitution should be used to rewrite 6(x + 5)^2+5(x + 5)-4 = 0 as a quadratic equation?\no u=(x + 5)\no u=(x - 5)\no u=(x + 5)^2\no u=(x - 5)^2

what substitution should be used to rewrite 6(x + 5)^2+5(x + 5)-4 = 0 as a quadratic equation?\no u=(x + 5)\no u=(x - 5)\no u=(x + 5)^2\no u=(x - 5)^2

Answer

Explanation:

Step1: Analyze the given equation

The equation is $6(x + 5)^2+5(x + 5)-4 = 0$. We want to rewrite it in the form of a quadratic equation $au^{2}+bu + c=0$. Notice that $(x + 5)$ appears in two terms.

Step2: Choose the substitution

If we let $u=(x + 5)$, then the equation becomes $6u^{2}+5u - 4=0$, which is a quadratic equation.

Answer:

A. $u=(x + 5)$