which subtraction expression has the difference 1 + 4i? (-2 + 6i)-(1 - 2i) (-2 + 6i)-(-1 - 2i) (3 + 5i)-(2…

which subtraction expression has the difference 1 + 4i? (-2 + 6i)-(1 - 2i) (-2 + 6i)-(-1 - 2i) (3 + 5i)-(2 - i) (3 + 5i)-(2 + i) done

which subtraction expression has the difference 1 + 4i? (-2 + 6i)-(1 - 2i) (-2 + 6i)-(-1 - 2i) (3 + 5i)-(2 - i) (3 + 5i)-(2 + i) done

Answer

Explanation:

Step1: Recall complex - number subtraction rule

$(a + bi)-(c+di)=(a - c)+(b - d)i$

Step2: Check option 1

$(-2 + 6i)-(1 - 2i)=(-2-1)+(6+2)i=-3 + 8i$

Step3: Check option 2

$(-2 + 6i)-(-1 - 2i)=(-2 + 1)+(6 + 2)i=-1+8i$

Step4: Check option 3

$(3 + 5i)-(2 - i)=(3 - 2)+(5+1)i=1 + 6i$

Step5: Check option 4

$(3 + 5i)-(2 + i)=(3 - 2)+(5 - 1)i=1+4i$

Answer:

$(3 + 5i)-(2 + i)$