what is the sum?\n$\frac{3}{x}+\frac{4}{x^{2}}$\n$\frac{3x + 4}{x^{3}}$\n$\frac{7}{x}$\n$\frac{3x +…
what is the sum?\n$\frac{3}{x}+\frac{4}{x^{2}}$\n$\frac{3x + 4}{x^{3}}$\n$\frac{7}{x}$\n$\frac{3x + 4}{x^{2}}$\n$\frac{7}{x + x^{2}}$
Answer
Explanation:
Step1: Find common denominator
The common denominator of $\frac{3}{x}$ and $\frac{4}{x^{2}}$ is $x^{2}$.
Step2: Rewrite fractions
Rewrite $\frac{3}{x}$ as $\frac{3x}{x^{2}}$ (by multiplying numerator and denominator by $x$). Then we have $\frac{3x}{x^{2}}+\frac{4}{x^{2}}$.
Step3: Add numerators
Since the denominators are the same, add the numerators: $\frac{3x + 4}{x^{2}}$.
Answer:
C. $\frac{3x + 4}{x^{2}}$