what is the sum?\n$\frac{2}{x^{2}}+\frac{4}{x^{2}}$\n$\frac{6}{x^{2}}$\n$\frac{6}{x^{4}}$\n$\frac{6}{2x^{2}}$…

what is the sum?\n$\frac{2}{x^{2}}+\frac{4}{x^{2}}$\n$\frac{6}{x^{2}}$\n$\frac{6}{x^{4}}$\n$\frac{6}{2x^{2}}$\n$\frac{8}{x^{2}}$
Answer
Answer:
A. $\frac{6}{x^{2}}$
Explanation:
Step1: Identify like - denominators
The fractions $\frac{2}{x^{2}}$ and $\frac{4}{x^{2}}$ have the same denominator $x^{2}$.
Step2: Apply fraction addition rule
For fractions $\frac{a}{c}+\frac{b}{c}=\frac{a + b}{c}$. Here $a = 2$, $b = 4$ and $c=x^{2}$. So $\frac{2}{x^{2}}+\frac{4}{x^{2}}=\frac{2 + 4}{x^{2}}$.
Step3: Calculate the numerator sum
$2+4 = 6$. So the sum is $\frac{6}{x^{2}}$.