what is the sum of the polynomials?\n11x² - 5\n+ x + 4\no 10x² - 9\no 11x² - x - 9\no 11x² + x - 1\no 12x² - 1

what is the sum of the polynomials?\n11x² - 5\n+ x + 4\no 10x² - 9\no 11x² - x - 9\no 11x² + x - 1\no 12x² - 1

what is the sum of the polynomials?\n11x² - 5\n+ x + 4\no 10x² - 9\no 11x² - x - 9\no 11x² + x - 1\no 12x² - 1

Answer

Explanation:

Step1: Combine like - terms

Combine the $x^2$ terms, $x$ terms, and constant terms separately. The $x^2$ term in the first polynomial is $11x^2$ with no $x^2$ term in the second polynomial. The $x$ term in the second polynomial is $x$ with no $x$ term in the first polynomial. The constant terms are $- 5$ and $4$.

Step2: Add the $x^2$ terms

The $x^2$ term in the sum is $11x^2$ since there is no other $x^2$ term to add to it.

Step3: Add the $x$ terms

The $x$ term in the sum is $x$ since there is only one $x$ - term.

Step4: Add the constant terms

$-5 + 4=-1$.

Step5: Write the sum of the polynomials

The sum of the polynomials $(11x^2-5)+(x + 4)$ is $11x^2+x-1$.

Answer:

$11x^2+x - 1$