what is the sum of the polynomials? (-x^2 + 9) + (-3x^2 - 11x + 4) -4x^2 - 2x + 4 -4x^2 - 11x + 13 2x^2 +…

what is the sum of the polynomials? (-x^2 + 9) + (-3x^2 - 11x + 4) -4x^2 - 2x + 4 -4x^2 - 11x + 13 2x^2 + 20x + 4 2x^2 + 11x + 5

what is the sum of the polynomials? (-x^2 + 9) + (-3x^2 - 11x + 4) -4x^2 - 2x + 4 -4x^2 - 11x + 13 2x^2 + 20x + 4 2x^2 + 11x + 5

Answer

Answer:

B. $-4x^{2}-11x + 13$

Explanation:

Step1: Remove parentheses

$(-x^{2}+9)+(-3x^{2}-11x + 4)=-x^{2}+9-3x^{2}-11x + 4$

Step2: Combine like - terms

Combine $x^{2}$ terms: $-x^{2}-3x^{2}=(-1 - 3)x^{2}=-4x^{2}$ There is only one $x$ term: $-11x$ Combine constant terms: $9 + 4=13$ So the sum is $-4x^{2}-11x + 13$