sylvia enlarged a photo to make a 24 x 32 inch poster using the dilation $d_{q,4}$. what are the dimensions…

Answer:

B. $6\times8$

Explanation:

Step1: Recall dilation formula

If a figure is dilated by a scale - factor $k$, the new dimensions $N$ and the original dimensions $O$ are related by $N = k\times O$. Here $k = 4$, and the new dimensions are $24\times32$.

Step2: Find original length

Let the original length be $l$ and new length be $L$. We know $L=k\times l$. Given $L = 32$ and $k = 4$, then $l=\frac{L}{k}=\frac{32}{4}=8$.

Step3: Find original width

Let the original width be $w$ and new width be $W$. We know $W = k\times w$. Given $W = 24$ and $k = 4$, then $w=\frac{W}{k}=\frac{24}{4}=6$. So the dimensions of the original photo are $6\times8$.