which system of equations could be graphed to solve the equation below? log(2x + 1)=3x - 2\no y1 = 3x, y2 =…

which system of equations could be graphed to solve the equation below? log(2x + 1)=3x - 2\no y1 = 3x, y2 = 2x\no y1 = log(2x + 1), y2 = 3x - 2\no y1 = log2x + 1, y2 = 3x - 2\no y1 = log(2x + 1 + 2), y2 = 3x

which system of equations could be graphed to solve the equation below? log(2x + 1)=3x - 2\no y1 = 3x, y2 = 2x\no y1 = log(2x + 1), y2 = 3x - 2\no y1 = log2x + 1, y2 = 3x - 2\no y1 = log(2x + 1 + 2), y2 = 3x

Answer

Answer:

B. $y_1=\log(2x + 1),y_2=3x - 2$

Explanation:

Step1: Recall equation - solving by graphing

To solve an equation $f(x)=g(x)$ by graphing, we set $y_1 = f(x)$ and $y_2=g(x)$.

Step2: Identify functions for given equation

For $\log(2x + 1)=3x - 2$, we set $y_1=\log(2x + 1)$ and $y_2=3x - 2$.