which system is equivalent to $\begin{cases}3x^{2}-4y^{2}=25\\-6x^{2}-2y^{2}=11end{cases}$?\n$\begin{cases}3x…

which system is equivalent to $\begin{cases}3x^{2}-4y^{2}=25\\-6x^{2}-2y^{2}=11end{cases}$?\n$\begin{cases}3x^{2}-4y^{2}=25\\12x^{2}+4y^{2}=22end{cases}$\n$\begin{cases}3x^{2}-4y^{2}=25\\-12x^{2}+4y^{2}=22end{cases}$\n$\begin{cases}6x^{2}-8y^{2}=25\\-6x^{2}-2y^{2}=11end{cases}$\n$\begin{cases}6x^{2}-8y^{2}=50\\-6x^{2}-2y^{2}=11end{cases}$

which system is equivalent to $\begin{cases}3x^{2}-4y^{2}=25\\-6x^{2}-2y^{2}=11end{cases}$?\n$\begin{cases}3x^{2}-4y^{2}=25\\12x^{2}+4y^{2}=22end{cases}$\n$\begin{cases}3x^{2}-4y^{2}=25\\-12x^{2}+4y^{2}=22end{cases}$\n$\begin{cases}6x^{2}-8y^{2}=25\\-6x^{2}-2y^{2}=11end{cases}$\n$\begin{cases}6x^{2}-8y^{2}=50\\-6x^{2}-2y^{2}=11end{cases}$

Answer

Answer:

[ \begin{cases} 6x^{2}-8y^{2}=50\ -6x^{2}-2y^{2}=11 \end{cases} ]

Explanation:

Step1: Multiply first - equation by 2

Multiply (3x^{2}-4y^{2}=25) by 2. [2(3x^{2}-4y^{2})=2\times25] [6x^{2}-8y^{2}=50] The second - equation (-6x^{2}-2y^{2}=11) remains the same. So the equivalent system is (\begin{cases}6x^{2}-8y^{2}=50\-6x^{2}-2y^{2}=11\end{cases})