the table represents an exponential function. what is the multiplicative rate of change of the…

the table represents an exponential function. what is the multiplicative rate of change of the function?\n|x|y|\n|1|3/2|\n|2|9/8|\n|3|27/32|\n|4|81/128|\noptions: 2/3, 3/4, 4/3, 3/2
Answer
Explanation:
Step1: Identify consecutive y-values from the table.
The table provides points $(x, y)$. For an exponential function, the multiplicative rate of change is the ratio of consecutive $y$-values when $x$ increases by 1. Let $y_1$ be the $y$-value when $x=1$, and $y_2$ be the $y$-value when $x=2$. From the table: $y_1 = \frac{3}{2}$ (for $x=1$) $y_2 = \frac{9}{8}$ (for $x=2$)
Step2: Calculate the ratio of the second y-value to the first y-value.
The multiplicative rate of change $b$ is given by $b = \frac{y_2}{y_1}$. $$b = \frac{\frac{9}{8}}{\frac{3}{2}}$$
Step3: Simplify the expression for the rate of change.
To divide fractions, multiply by the reciprocal of the divisor. $$b = \frac{9}{8} \times \frac{2}{3}$$ $$b = \frac{9 \times 2}{8 \times 3}$$ $$b = \frac{18}{24}$$
Step4: Reduce the fraction to its simplest form.
Divide both the numerator and the denominator by their greatest common divisor, which is 6. $$b = \frac{18 \div 6}{24 \div 6}$$ $$b = \frac{3}{4}$$ To verify, we can use another pair of consecutive y-values, for example, $y_3 = \frac{27}{32}$ (for $x=3$) and $y_2 = \frac{9}{8}$ (for $x=2$). $$b = \frac{y_3}{y_2} = \frac{\frac{27}{32}}{\frac{9}{8}} = \frac{27}{32} \times \frac{8}{9} = \frac{27 \times 8}{32 \times 9} = \frac{216}{288}$$ Simplifying $\frac{216}{288}$ by dividing by their greatest common divisor, 72: $$b = \frac{216 \div 72}{288 \div 72} = \frac{3}{4}$$ The multiplicative rate of change is consistent.
Answer:
B. $\frac{3}{4}$