triangle abc is an equilateral triangle. segment ad measures 18 inches. which statements about the diagram…

triangle abc is an equilateral triangle. segment ad measures 18 inches. which statements about the diagram are correct? check all that apply. bd = 9 in. ab = 36 in. dc = 6√3 in. ac = 12√3 in. bc = 18√3 in.

triangle abc is an equilateral triangle. segment ad measures 18 inches. which statements about the diagram are correct? check all that apply. bd = 9 in. ab = 36 in. dc = 6√3 in. ac = 12√3 in. bc = 18√3 in.

Answer

Answer:

  • A. BD = 9 in.
  • D. AC = 12√3 in.
  • E. BC = 12√3 in.

Explanation:

Step1: Recall equilateral - triangle properties

In an equilateral triangle (ABC) with (AD\perp BC), (BD = DC=\frac{1}{2}BC) and (\angle B = 60^{\circ}), (\angle BAD=30^{\circ}).

Step2: Use 30 - 60 - 90 triangle ratios

In right - triangle (ABD), if the side opposite the (30^{\circ}) angle is (x), the side opposite the (60^{\circ}) angle ((AD)) is (x\sqrt{3}), and the hypotenuse ((AB)) is (2x). Given (AD = 18) inches. Let (BD=x), then (AD=x\sqrt{3}). Since (AD = 18), we have (x\sqrt{3}=18), so (x = BD=DC = 6\sqrt{3}) inches.

Step3: Calculate side lengths of the equilateral triangle

The side length of the equilateral triangle (AB = AC=BC = 2x=12\sqrt{3}) inches.

  • For (BD): Since (AD) is the perpendicular bisector of (BC) in equilateral (\triangle ABC), and using the 30 - 60 - 90 triangle relationship in (\triangle ABD) where (AD = 18) and (\angle BAD = 30^{\circ}), (BD=\frac{18}{\sqrt{3}}=6\sqrt{3}\neq9), so the statement (BD = 9) in. is incorrect.
  • For (AB): Using the 30 - 60 - 90 triangle relationship in (\triangle ABD), if (BD=x) and (AD = 18=x\sqrt{3}), then (x = 6\sqrt{3}) and (AB = 2x=12\sqrt{3}\neq36), so the statement (AB = 36) in. is incorrect.
  • For (DC): Since (AD) is the perpendicular bisector of (BC) in equilateral (\triangle ABC), (DC = BD). From (AD = 18) and the 30 - 60 - 90 triangle relationship ((AD=\sqrt{3}BD)), (BD=DC = 6\sqrt{3}) inches, this statement is correct.
  • For (AC): In right - triangle (ADC), (AD = 18), (DC = 6\sqrt{3}). By the Pythagorean theorem (AC=\sqrt{AD^{2}+DC^{2}}=\sqrt{18^{2}+(6\sqrt{3})^{2}}=\sqrt{324 + 108}=\sqrt{432}=12\sqrt{3}) inches, this statement is correct.
  • For (BC): Since (BC = 2BD) and (BD = 6\sqrt{3}), (BC=12\sqrt{3}) inches, this statement is correct.