triangle def is isosceles, where $overline{df}congoverline{fe}$. angle fde is bisected by segment dg…

triangle def is isosceles, where $overline{df}congoverline{fe}$. angle fde is bisected by segment dg, creating angle gde with a measure of 29°. what is the measure of angle dfe? 29° 32° 58° 64°

triangle def is isosceles, where $overline{df}congoverline{fe}$. angle fde is bisected by segment dg, creating angle gde with a measure of 29°. what is the measure of angle dfe? 29° 32° 58° 64°

Answer

Explanation:

Step1: Find angle FDE

Since segment DG bisects angle FDE and angle GDE = 29°, then angle FDE=2×angle GDE. angle FDE = 2×29° = 58°

Step2: Use isosceles - triangle property

In isosceles triangle DEF where DF = FE, angle FDE = angle FED = 58°.

Step3: Calculate angle DFE

By the angle - sum property of a triangle (the sum of interior angles of a triangle is 180°), let angle DFE=x. Then x + 58°+58° = 180°. x=180°-(58° + 58°)=64°

Answer:

64°