triangle mnp is dilated according to the rule ( d_{0,1.5}(x,y)\to(1.5x,1.5y) ) to create the image triangle…

triangle mnp is dilated according to the rule ( d_{0,1.5}(x,y)\to(1.5x,1.5y) ) to create the image triangle ( mnp ), which is not shown. what are the coordinates of the endpoints of segment ( mn )? ( m(-6,9) ) and ( n(4,9) ) ( m(-6,9) ) and ( n(3,9) ) ( m(-2,3) ) and ( n(7,9) ) ( m(-2,3) ) and ( n(1,3) )

triangle mnp is dilated according to the rule ( d_{0,1.5}(x,y)\to(1.5x,1.5y) ) to create the image triangle ( mnp ), which is not shown. what are the coordinates of the endpoints of segment ( mn )? ( m(-6,9) ) and ( n(4,9) ) ( m(-6,9) ) and ( n(3,9) ) ( m(-2,3) ) and ( n(7,9) ) ( m(-2,3) ) and ( n(1,3) )

Answer

Explanation:

Step1: Find the coordinates of (M) and (N)

From the graph, the coordinates of (M) are ((- 4,6)) and the coordinates of (N) are ((2,6))

Step2: Apply the dilation rule (D_{0,1.5}(x,y)\to(1.5x,1.5y))

For point (M(-4,6)): (x = - 4,y = 6) After dilation, (x'=1.5\times(-4)=-6), (y'=1.5\times6 = 9) So (M'(-6,9)) For point (N(2,6)): (x = 2,y = 6) After dilation, (x'=1.5\times2 = 3), (y'=1.5\times6=9) So (N'(3,9))

Answer:

(M'(-6,9)) and (N'(3,9)) (corresponding to the second option (M'(-6,9)) and (N'(3,9)))