triangle qrs is to be dilated using the rule $d_{p,\frac{3}{4}}$. what will be the distance from the center…

triangle qrs is to be dilated using the rule $d_{p,\frac{3}{4}}$. what will be the distance from the center of dilation, p, to the image s? 2 units 4 units 6 units 8 units
Answer
Explanation:
Step1: Recall dilation formula
The distance from the center of dilation $P$ to a point $S$ is $d(PS) = 8$ units. The rule of dilation is $D_{P,\frac{3}{4}}$, which means the scale - factor $k=\frac{3}{4}$. The distance from the center of dilation $P$ to the image $S'$ is given by $d(PS')=k\times d(PS)$.
Step2: Calculate the distance
Substitute $k = \frac{3}{4}$ and $d(PS)=8$ into the formula $d(PS')=k\times d(PS)$. So $d(PS')=\frac{3}{4}\times8$. $d(PS') = 6$ units.
Answer:
6 units