for the triangles to be congruent by hl, what must be the value of x? 2 3 4 7

for the triangles to be congruent by hl, what must be the value of x? 2 3 4 7

for the triangles to be congruent by hl, what must be the value of x? 2 3 4 7

Answer

Answer:

C. 4

Explanation:

Step1: Identify hypotenuse and leg for HL

In right - triangle ABC, hypotenuse (AC = 15) and leg (BC=12). In right - triangle FGH, hypotenuse (FH) and leg (FG = 2x + 1). For the triangles to be congruent by HL (Hypotenuse - Leg), the hypotenuses must be equal and one pair of legs must be equal. Let's assume the legs are equal, so (2x+1 = 12).

Step2: Solve the equation for (x)

[ \begin{align*} 2x+1&=12\ 2x&=12 - 1\ 2x&=11\ x&=\frac{11}{2} \end{align*} ] This is wrong. Let's assume the hypotenuses are equal. So (3x + 3=15).

Step3: Solve the new equation for (x)

[ \begin{align*} 3x+3&=15\ 3x&=15 - 3\ 3x&=12\ x& = 4 \end{align*} ]