which is true about the solution to the system of inequalities shown?\ny≥3x + 1\ny≤3x - 3\nonly values that…

which is true about the solution to the system of inequalities shown?\ny≥3x + 1\ny≤3x - 3\nonly values that satisfy y≥3x + 1 are solutions.\nonly values that satisfy y≤3x - 3 are solutions.\nvalues that satisfy either y≥3x + 1 or y≤3x - 3 are solutions.\nthere are no solutions.
Answer
Answer:
There are no solutions.
Explanation:
Step1: Analyze the slopes
The two inequalities $y\geq3x + 1$ and $y\leq3x-3$ have the same slope $m = 3$.
Step2: Consider the y - intercepts
The first line has a y - intercept of $b_1=1$ and the second has $b_2=-3$.
Step3: Determine the solution set
The region above $y = 3x+1$ and the region below $y = 3x - 3$ do not overlap. So there are no values of $x$ and $y$ that satisfy both inequalities simultaneously.