which is true about the solution to the system of inequalities shown?\n$y\\leq\\frac{1}{3}x…

which is true about the solution to the system of inequalities shown?\n$y\\leq\\frac{1}{3}x - 1$\n$y\\leq\\frac{1}{3}x - 3$\nall values that satisfy $y\\leq\\frac{1}{3}x - 1$ are solutions.\nall values that satisfy $y\\leq\\frac{1}{3}x - 3$ are solutions.

which is true about the solution to the system of inequalities shown?\n$y\\leq\\frac{1}{3}x - 1$\n$y\\leq\\frac{1}{3}x - 3$\nall values that satisfy $y\\leq\\frac{1}{3}x - 1$ are solutions.\nall values that satisfy $y\\leq\\frac{1}{3}x - 3$ are solutions.

Answer

Explanation:

Step1: Analyze the system of inequalities

Both inequalities have the same slope ($\frac{1}{3}$) and different y-intercepts ($-1$ and $-3$), so they are parallel lines.

Step2: Determine the solution region

Since $y \leq \frac{1}{3}x - 3$ is below $y \leq \frac{1}{3}x - 1$, the intersection (solution) is the region satisfying the stricter (lower) inequality.

Answer:

All values that satisfy ( y \leq \frac{1}{3}x - 3 ) are solutions.